fluentbit (2) 썸네일형 리스트형 Using Lua filter to find if log matches a pattern, and remove last n characters. Original log: [1646213018.112301921, {"log"=>"testtest1-"} Changed log : [1646213018.112301921, {"log"=>"testtest1"} [FILTER] Name lua Match test.* script checkend.lua call check_end If you use lua filter, you can find "If a log/word matches a specific pattern", and do some works. ex) if the condition suits, remove last n characters. I wrote on those codes on fluentbit configmap, so there is tab.. Remove last n characters using Regex & Fluent Bit I took a quite a munutes to find "remove / delete last n characters / words by regex" but there was no explicit answer. However, I found a solution. [FILTER] Name parser Match test.* Key_Name path Parser removelastn Reserve_Data On Preserve_key On [PARSER] Name removelastn Format regex Regex (?.*?).{6}$ link (?.*?) means "log" might not exist, anyway it catch all characters or nothing("") .{6}$ .. 이전 1 다음
